Base | Representation |
---|---|
bin | 11011110010100010100111… |
… | …100001110101100100010011 |
3 | 121000202011012211011222122210 |
4 | 123302202213201311210103 |
5 | 112004424334402241321 |
6 | 1111535135431403203 |
7 | 34513063310133144 |
oct | 3362424741654423 |
9 | 530664184158583 |
10 | 122220400040211 |
11 | 35a414205a8360 |
12 | 1185b170823503 |
13 | 5327446511805 |
14 | 22276db09bacb |
15 | e1e3769e3b76 |
hex | 6f28a7875913 |
122220400040211 has 64 divisors (see below), whose sum is σ = 188903676358656. Its totient is φ = 69467220480000.
The previous prime is 122220400040197. The next prime is 122220400040293. The reversal of 122220400040211 is 112040004022221.
It is not a de Polignac number, because 122220400040211 - 222 = 122220395845907 is a prime.
It is not an unprimeable number, because it can be changed into a prime (122220400040911) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1150722270 + ... + 1150828476.
It is an arithmetic number, because the mean of its divisors is an integer number (2951619943104).
Almost surely, 2122220400040211 is an apocalyptic number.
122220400040211 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
122220400040211 is a deficient number, since it is larger than the sum of its proper divisors (66683276318445).
122220400040211 is a wasteful number, since it uses less digits than its factorization.
122220400040211 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 113532.
The product of its (nonzero) digits is 512, while the sum is 21.
Adding to 122220400040211 its reverse (112040004022221), we get a palindrome (234260404062432).
The spelling of 122220400040211 in words is "one hundred twenty-two trillion, two hundred twenty billion, four hundred million, forty thousand, two hundred eleven".
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