Base | Representation |
---|---|
bin | 1011000111011011001111… |
… | …1000111010111011001001 |
3 | 1121021102122010120122110112 |
4 | 2301312303320322323021 |
5 | 3100222031200001301 |
6 | 41554445015124105 |
7 | 2401011336603122 |
oct | 261666370727311 |
9 | 47242563518415 |
10 | 12222200000201 |
11 | 39924512a4804 |
12 | 14548b2073635 |
13 | 6a8719118149 |
14 | 3037b4223049 |
15 | 162dda32c9bb |
hex | b1db3e3aec9 |
12222200000201 has 4 divisors (see below), whose sum is σ = 12506437209552. Its totient is φ = 11937962790852.
The previous prime is 12222200000183. The next prime is 12222200000293. The reversal of 12222200000201 is 10200000222221.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 12222200000201 - 226 = 12222132891337 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12222200000501) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 142118604611 + ... + 142118604696.
It is an arithmetic number, because the mean of its divisors is an integer number (3126609302388).
Almost surely, 212222200000201 is an apocalyptic number.
It is an amenable number.
12222200000201 is a deficient number, since it is larger than the sum of its proper divisors (284237209351).
12222200000201 is an equidigital number, since it uses as much as digits as its factorization.
12222200000201 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 284237209350.
The product of its (nonzero) digits is 64, while the sum is 14.
Adding to 12222200000201 its reverse (10200000222221), we get a palindrome (22422200222422).
The spelling of 12222200000201 in words is "twelve trillion, two hundred twenty-two billion, two hundred million, two hundred one", and thus it is an aban number.
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