Base | Representation |
---|---|
bin | 10001110010010011001… |
… | …100000101010100100111 |
3 | 11022211211000102210100200 |
4 | 101302103030011110213 |
5 | 130011121433132333 |
6 | 2333253411441543 |
7 | 154206151456131 |
oct | 21622314052447 |
9 | 4284730383320 |
10 | 1222240130343 |
11 | 431392765201 |
12 | 178a658b62b3 |
13 | 8b345104c4b |
14 | 4322a136051 |
15 | 21bd744dc13 |
hex | 11c93305527 |
1222240130343 has 6 divisors (see below), whose sum is σ = 1765457966064. Its totient is φ = 814826753556.
The previous prime is 1222240130323. The next prime is 1222240130381. The reversal of 1222240130343 is 3430310422221.
1222240130343 is a `hidden beast` number, since 1 + 2 + 222 + 401 + 3 + 0 + 34 + 3 = 666.
It is not a de Polignac number, because 1222240130343 - 213 = 1222240122151 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1222240130323) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 67902229455 + ... + 67902229472.
It is an arithmetic number, because the mean of its divisors is an integer number (294242994344).
Almost surely, 21222240130343 is an apocalyptic number.
1222240130343 is a deficient number, since it is larger than the sum of its proper divisors (543217835721).
1222240130343 is a wasteful number, since it uses less digits than its factorization.
1222240130343 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 135804458933 (or 135804458930 counting only the distinct ones).
The product of its (nonzero) digits is 6912, while the sum is 27.
Adding to 1222240130343 its reverse (3430310422221), we get a palindrome (4652550552564).
The spelling of 1222240130343 in words is "one trillion, two hundred twenty-two billion, two hundred forty million, one hundred thirty thousand, three hundred forty-three".
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