Base | Representation |
---|---|
bin | 10110110001001001… |
… | …11101000010010001 |
3 | 1011112212200011022021 |
4 | 23120210331002101 |
5 | 200013204003213 |
6 | 5340532011441 |
7 | 611624016334 |
oct | 133044750221 |
9 | 34485604267 |
10 | 12223500433 |
11 | 5202935881 |
12 | 2451760b81 |
13 | 11ca5595c1 |
14 | 83d59a61b |
15 | 4b81bcd8d |
hex | 2d893d091 |
12223500433 has 8 divisors (see below), whose sum is σ = 12426079680. Its totient is φ = 12020992080.
The previous prime is 12223500391. The next prime is 12223500469. The reversal of 12223500433 is 33400532221.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 12223500433 - 225 = 12189946001 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 12223500398 and 12223500407.
It is not an unprimeable number, because it can be changed into a prime (12223500473) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 417666 + ... + 445972.
It is an arithmetic number, because the mean of its divisors is an integer number (1553259960).
Almost surely, 212223500433 is an apocalyptic number.
It is an amenable number.
12223500433 is a deficient number, since it is larger than the sum of its proper divisors (202579247).
12223500433 is an equidigital number, since it uses as much as digits as its factorization.
12223500433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 35447.
The product of its (nonzero) digits is 4320, while the sum is 25.
It can be divided in two parts, 12223 and 500433, that added together give a square (512656 = 7162).
The spelling of 12223500433 in words is "twelve billion, two hundred twenty-three million, five hundred thousand, four hundred thirty-three".
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