Base | Representation |
---|---|
bin | 111000111011000101… |
… | …0000110101001010001 |
3 | 102200112012211210012221 |
4 | 1301312022012221101 |
5 | 4000322302210213 |
6 | 132053522221041 |
7 | 11555154063553 |
oct | 1616612065121 |
9 | 380465753187 |
10 | 122241444433 |
11 | 4792a121539 |
12 | 1b8364b4781 |
13 | b6b1699b54 |
14 | 5cb8cd14d3 |
15 | 32a6b5c38d |
hex | 1c76286a51 |
122241444433 has 4 divisors (see below), whose sum is σ = 122281938160. Its totient is φ = 122200950708.
The previous prime is 122241444419. The next prime is 122241444443. The reversal of 122241444433 is 334444142221.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 122241444433 - 25 = 122241444401 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (122241444443) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20242335 + ... + 20248372.
It is an arithmetic number, because the mean of its divisors is an integer number (30570484540).
Almost surely, 2122241444433 is an apocalyptic number.
It is an amenable number.
122241444433 is a deficient number, since it is larger than the sum of its proper divisors (40493727).
122241444433 is an equidigital number, since it uses as much as digits as its factorization.
122241444433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 40493726.
The product of its digits is 73728, while the sum is 34.
Adding to 122241444433 its reverse (334444142221), we get a palindrome (456685586654).
The spelling of 122241444433 in words is "one hundred twenty-two billion, two hundred forty-one million, four hundred forty-four thousand, four hundred thirty-three".
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