Base | Representation |
---|---|
bin | 11011110011111000000001… |
… | …100000110011010001100111 |
3 | 121001001220220211102102011111 |
4 | 123303320001200303101213 |
5 | 112012430142113000320 |
6 | 1112045223242245451 |
7 | 34522520650163641 |
oct | 3363700140632147 |
9 | 531056824372144 |
10 | 122312104031335 |
11 | 35a772aa068179 |
12 | 11874aa41b6887 |
13 | 5332c9c379b5a |
14 | 222bd1a3dd891 |
15 | e21942761a5a |
hex | 6f3e01833467 |
122312104031335 has 16 divisors (see below), whose sum is σ = 147720100316256. Its totient is φ = 97221098103808.
The previous prime is 122312104031309. The next prime is 122312104031353. The reversal of 122312104031335 is 533130401213221.
It is not a de Polignac number, because 122312104031335 - 211 = 122312104029287 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 122312104031297 and 122312104031306.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 111863794 + ... + 112951903.
It is an arithmetic number, because the mean of its divisors is an integer number (9232506269766).
Almost surely, 2122312104031335 is an apocalyptic number.
122312104031335 is a deficient number, since it is larger than the sum of its proper divisors (25407996284921).
122312104031335 is a wasteful number, since it uses less digits than its factorization.
122312104031335 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 224816402.
The product of its (nonzero) digits is 12960, while the sum is 31.
Adding to 122312104031335 its reverse (533130401213221), we get a palindrome (655442505244556).
The spelling of 122312104031335 in words is "one hundred twenty-two trillion, three hundred twelve billion, one hundred four million, thirty-one thousand, three hundred thirty-five".
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