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122313104450434 = 261156552225217
BaseRepresentation
bin11011110011111000111101…
…001001000110001110000010
3121001002000111112212222011201
4123303320331021012032002
5112012434214214403214
61112045510420531414
734522554515461462
oct3363707511061602
9531060445788151
10122313104450434
1135a77772847917
1211875123250b6a
1353330cb702a11
14222bdb3219ba2
15e219a04c7274
hex6f3e3d246382

122313104450434 has 4 divisors (see below), whose sum is σ = 183469656675654. Its totient is φ = 61156552225216.

The previous prime is 122313104450393. The next prime is 122313104450441. The reversal of 122313104450434 is 434054401313221.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 117540832640625 + 4772271809809 = 10841625^2 + 2184553^2 .

It is a junction number, because it is equal to n+sod(n) for n = 122313104450393 and 122313104450402.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30578276112607 + ... + 30578276112610.

Almost surely, 2122313104450434 is an apocalyptic number.

122313104450434 is a deficient number, since it is larger than the sum of its proper divisors (61156552225220).

122313104450434 is an equidigital number, since it uses as much as digits as its factorization.

122313104450434 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 61156552225219.

The product of its (nonzero) digits is 138240, while the sum is 37.

Adding to 122313104450434 its reverse (434054401313221), we get a palindrome (556367505763655).

The spelling of 122313104450434 in words is "one hundred twenty-two trillion, three hundred thirteen billion, one hundred four million, four hundred fifty thousand, four hundred thirty-four".

Divisors: 1 2 61156552225217 122313104450434