Base | Representation |
---|---|
bin | 1011000111111101100001… |
… | …0000010011011101111101 |
3 | 1121022022101022002022112202 |
4 | 2301333120100103131331 |
5 | 3100344401402410123 |
6 | 42003005544041245 |
7 | 2401455331644344 |
oct | 261773020233575 |
9 | 47268338068482 |
10 | 12231400044413 |
11 | 39963424a9130 |
12 | 145663b163225 |
13 | 6a95541698a4 |
14 | 30400802cb5b |
15 | 163277d71a28 |
hex | b1fd841377d |
12231400044413 has 8 divisors (see below), whose sum is σ = 13923490959936. Its totient is φ = 10636000038400.
The previous prime is 12231400044341. The next prime is 12231400044421. The reversal of 12231400044413 is 31444000413221.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 12231400044413 - 212 = 12231400040317 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12231400044113) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 24172727108 + ... + 24172727613.
It is an arithmetic number, because the mean of its divisors is an integer number (1740436369992).
Almost surely, 212231400044413 is an apocalyptic number.
It is an amenable number.
12231400044413 is a deficient number, since it is larger than the sum of its proper divisors (1692090915523).
12231400044413 is a wasteful number, since it uses less digits than its factorization.
12231400044413 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 48345454755.
The product of its (nonzero) digits is 9216, while the sum is 29.
Adding to 12231400044413 its reverse (31444000413221), we get a palindrome (43675400457634).
The spelling of 12231400044413 in words is "twelve trillion, two hundred thirty-one billion, four hundred million, forty-four thousand, four hundred thirteen".
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