Base | Representation |
---|---|
bin | 11011110011111010110110… |
… | …100011000110011111010111 |
3 | 121001002012202111121011210120 |
4 | 123303322312203012133113 |
5 | 112013002402133413143 |
6 | 1112050444501523023 |
7 | 34522656140503005 |
oct | 3363726643063727 |
9 | 531065674534716 |
10 | 122315141310423 |
11 | 35a7861857a986 |
12 | 118755b1413473 |
13 | 53333646b4609 |
14 | 222c12794ba75 |
15 | e21a6e21b383 |
hex | 6f3eb68c67d7 |
122315141310423 has 8 divisors (see below), whose sum is σ = 163101365923200. Its totient is φ = 81536172118968.
The previous prime is 122315141310419. The next prime is 122315141310463. The reversal of 122315141310423 is 324013141513221.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 122315141310423 - 22 = 122315141310419 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (122315141310413) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1813815993 + ... + 1813883426.
It is an arithmetic number, because the mean of its divisors is an integer number (20387670740400).
Almost surely, 2122315141310423 is an apocalyptic number.
122315141310423 is a deficient number, since it is larger than the sum of its proper divisors (40786224612777).
122315141310423 is a wasteful number, since it uses less digits than its factorization.
122315141310423 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3627710661.
The product of its (nonzero) digits is 17280, while the sum is 33.
Adding to 122315141310423 its reverse (324013141513221), we get a palindrome (446328282823644).
The spelling of 122315141310423 in words is "one hundred twenty-two trillion, three hundred fifteen billion, one hundred forty-one million, three hundred ten thousand, four hundred twenty-three".
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