Base | Representation |
---|---|
bin | 1011000111111111111010… |
… | …1000111100111110110010 |
3 | 1121022101001011212200120101 |
4 | 2301333332220330332302 |
5 | 3100402211233240424 |
6 | 42003153511103014 |
7 | 2401510311553003 |
oct | 261777650747662 |
9 | 47271034780511 |
10 | 12232044040114 |
11 | 3996642a76688 |
12 | 145679a971a6a |
13 | 6a96276ca932 |
14 | 3040697891aa |
15 | 1632b4680344 |
hex | b1ffea3cfb2 |
12232044040114 has 4 divisors (see below), whose sum is σ = 18348066060174. Its totient is φ = 6116022020056.
The previous prime is 12232044040091. The next prime is 12232044040121. The reversal of 12232044040114 is 41104044023221.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 8793923357025 + 3438120683089 = 2965455^2 + 1854217^2 .
It is a super-2 number, since 2×122320440401142 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3058011010027 + ... + 3058011010030.
Almost surely, 212232044040114 is an apocalyptic number.
12232044040114 is a deficient number, since it is larger than the sum of its proper divisors (6116022020060).
12232044040114 is an equidigital number, since it uses as much as digits as its factorization.
12232044040114 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6116022020059.
The product of its (nonzero) digits is 6144, while the sum is 28.
Adding to 12232044040114 its reverse (41104044023221), we get a palindrome (53336088063335).
The spelling of 12232044040114 in words is "twelve trillion, two hundred thirty-two billion, forty-four million, forty thousand, one hundred fourteen".
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