Base | Representation |
---|---|
bin | 11011110100001001101010… |
… | …001100100011110110010111 |
3 | 121001010201210112011120002202 |
4 | 123310021222030203312113 |
5 | 112013232432242432020 |
6 | 1112102034250155115 |
7 | 34524061134033662 |
oct | 3364115214436627 |
9 | 531121715146082 |
10 | 122331040202135 |
11 | 35a84337037606 |
12 | 118786a9a22a9b |
13 | 53349c952974b |
14 | 222cbd52c06d9 |
15 | e2219eddde75 |
hex | 6f426a323d97 |
122331040202135 has 8 divisors (see below), whose sum is σ = 146853256365216. Its totient is φ = 97827493413280.
The previous prime is 122331040202057. The next prime is 122331040202191. The reversal of 122331040202135 is 531202040133221.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 122331040202135 - 244 = 104738854157719 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 122331040202098 and 122331040202107.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4667329139 + ... + 4667355348.
It is an arithmetic number, because the mean of its divisors is an integer number (18356657045652).
Almost surely, 2122331040202135 is an apocalyptic number.
122331040202135 is a deficient number, since it is larger than the sum of its proper divisors (24522216163081).
122331040202135 is an equidigital number, since it uses as much as digits as its factorization.
122331040202135 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9334687113.
The product of its (nonzero) digits is 8640, while the sum is 29.
Adding to 122331040202135 its reverse (531202040133221), we get a palindrome (653533080335356).
The spelling of 122331040202135 in words is "one hundred twenty-two trillion, three hundred thirty-one billion, forty million, two hundred two thousand, one hundred thirty-five".
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