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12233333110133 = 34457355031869
BaseRepresentation
bin1011001000000100101101…
…1110010111010101110101
31121022111101000111020012102
42302001023132113111311
53100412331234011013
642003525440231445
72401554253511432
oct262011336272565
947274330436172
1012233333110133
113997144689003
121456a9a60b585
136a97a17a9965
1430414ca62b89
1516333c911d58
hexb204b797575

12233333110133 has 4 divisors (see below), whose sum is σ = 12233688176460. Its totient is φ = 12232978043808.

The previous prime is 12233333110129. The next prime is 12233333110147. The reversal of 12233333110133 is 33101133333221.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 6407008876849 + 5826324233284 = 2531207^2 + 2413778^2 .

It is a cyclic number.

It is not a de Polignac number, because 12233333110133 - 22 = 12233333110129 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 12233333110096 and 12233333110105.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12233833110133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 177481478 + ... + 177550391.

It is an arithmetic number, because the mean of its divisors is an integer number (3058422044115).

Almost surely, 212233333110133 is an apocalyptic number.

It is an amenable number.

12233333110133 is a deficient number, since it is larger than the sum of its proper divisors (355066327).

12233333110133 is an equidigital number, since it uses as much as digits as its factorization.

12233333110133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 355066326.

The product of its (nonzero) digits is 8748, while the sum is 29.

Adding to 12233333110133 its reverse (33101133333221), we get a palindrome (45334466443354).

The spelling of 12233333110133 in words is "twelve trillion, two hundred thirty-three billion, three hundred thirty-three million, one hundred ten thousand, one hundred thirty-three".

Divisors: 1 34457 355031869 12233333110133