Base | Representation |
---|---|
bin | 10110110010011101… |
… | …01110100100000011 |
3 | 1011120122021111221100 |
4 | 23121032232210003 |
5 | 200024004414303 |
6 | 5342002425443 |
7 | 612116055642 |
oct | 133116564403 |
9 | 34518244840 |
10 | 12234451203 |
11 | 52090352a7 |
12 | 2455362283 |
13 | 11cc8c1b50 |
14 | 840c0b359 |
15 | 4b91328a3 |
hex | 2d93ae903 |
12234451203 has 72 divisors (see below), whose sum is σ = 20361893552. Its totient is φ = 7032541824.
The previous prime is 12234451189. The next prime is 12234451261. The reversal of 12234451203 is 30215443221.
12234451203 is a `hidden beast` number, since 1 + 2 + 2 + 3 + 4 + 451 + 203 = 666.
12234451203 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 12234451203 - 25 = 12234451171 is a prime.
It is not an unprimeable number, because it can be changed into a prime (12234451283) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 2659101 + ... + 2663697.
Almost surely, 212234451203 is an apocalyptic number.
12234451203 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
12234451203 is a deficient number, since it is larger than the sum of its proper divisors (8127442349).
12234451203 is a wasteful number, since it uses less digits than its factorization.
12234451203 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4705 (or 4679 counting only the distinct ones).
The product of its (nonzero) digits is 5760, while the sum is 27.
Adding to 12234451203 its reverse (30215443221), we get a palindrome (42449894424).
The spelling of 12234451203 in words is "twelve billion, two hundred thirty-four million, four hundred fifty-one thousand, two hundred three".
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