Base | Representation |
---|---|
bin | 1011001000001011011010… |
… | …1110100000100010101010 |
3 | 1121022200000102100220212101 |
4 | 2302002312232200202222 |
5 | 3100430022410113414 |
6 | 42004424155404014 |
7 | 2401646663223403 |
oct | 262026656404252 |
9 | 47280012326771 |
10 | 12235132504234 |
11 | 3997988369472 |
12 | 145730115360a |
13 | 6a99ca516cb3 |
14 | 30427da1c9aa |
15 | 1633e589aa74 |
hex | b20b6ba08aa |
12235132504234 has 4 divisors (see below), whose sum is σ = 18352698756354. Its totient is φ = 6117566252116.
The previous prime is 12235132504207. The next prime is 12235132504241. The reversal of 12235132504234 is 43240523153221.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 6167300394025 + 6067832110209 = 2483405^2 + 2463297^2 .
It is a junction number, because it is equal to n+sod(n) for n = 12235132504193 and 12235132504202.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3058783126057 + ... + 3058783126060.
Almost surely, 212235132504234 is an apocalyptic number.
12235132504234 is a deficient number, since it is larger than the sum of its proper divisors (6117566252120).
12235132504234 is an equidigital number, since it uses as much as digits as its factorization.
12235132504234 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6117566252119.
The product of its (nonzero) digits is 172800, while the sum is 37.
Adding to 12235132504234 its reverse (43240523153221), we get a palindrome (55475655657455).
The spelling of 12235132504234 in words is "twelve trillion, two hundred thirty-five billion, one hundred thirty-two million, five hundred four thousand, two hundred thirty-four".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.085 sec. • engine limits •