Base | Representation |
---|---|
bin | 1011001000011111000011… |
… | …0110000110011110100011 |
3 | 1121100011121200212111110221 |
4 | 2302013300312012132203 |
5 | 3101021321022243301 |
6 | 42011055134503511 |
7 | 2402224404622441 |
oct | 262076066063643 |
9 | 47304550774427 |
10 | 12240402540451 |
11 | 399a1421446a8 |
12 | 1458332064b97 |
13 | 6aa35a2b2017 |
14 | 30461d8d3b91 |
15 | 163603392da1 |
hex | b21f0d867a3 |
12240402540451 has 4 divisors (see below), whose sum is σ = 12412802576304. Its totient is φ = 12068002504600.
The previous prime is 12240402540439. The next prime is 12240402540479. The reversal of 12240402540451 is 15404520404221.
12240402540451 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12240402540451 - 219 = 12240402016163 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12240402540481) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 86200017820 + ... + 86200017961.
It is an arithmetic number, because the mean of its divisors is an integer number (3103200644076).
Almost surely, 212240402540451 is an apocalyptic number.
12240402540451 is a deficient number, since it is larger than the sum of its proper divisors (172400035853).
12240402540451 is an equidigital number, since it uses as much as digits as its factorization.
12240402540451 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 172400035852.
The product of its (nonzero) digits is 51200, while the sum is 34.
Adding to 12240402540451 its reverse (15404520404221), we get a palindrome (27644922944672).
The spelling of 12240402540451 in words is "twelve trillion, two hundred forty billion, four hundred two million, five hundred forty thousand, four hundred fifty-one".
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