12240431420113 has 4 divisors (see below), whose sum is σ = 13182003067828. Its totient is φ = 11298859772400.

The previous prime is 12240431420069. The next prime is 12240431420159. The reversal of 12240431420113 is 31102413404221.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 6304834749249 + 5935596670864 = 2510943^2 + 2436308^2 .

It is a cyclic number.

It is not a de Polignac number, because 12240431420113 - 2²⁵ = 12240397865681 is a prime.

It is a super-2 number, since 2×12240431420113² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12240431420513) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 470785823838 + ... + 470785823863.

It is an arithmetic number, because the mean of its divisors is an integer number (3295500766957).

Almost surely, 2^{12240431420113} is an apocalyptic number.

12240431420113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

12240431420113 is a deficient number, since it is larger than the sum of its proper divisors (941571647715).

12240431420113 is an equidigital number, since it uses as much as digits as its factorization.

12240431420113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 941571647714.

The product of its (nonzero) digits is 4608, while the sum is 28.

Adding to 12240431420113 its reverse (31102413404221), we get a palindrome (43342844824334).

The spelling of 12240431420113 in words is "twelve trillion, two hundred forty billion, four hundred thirty-one million, four hundred twenty thousand, one hundred thirteen".