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12241444153 = 21158016323
BaseRepresentation
bin10110110011010010…
…11001110100111001
31011121010102210110111
423121221121310321
5200032302203103
65342412344321
7612232362361
oct133151316471
934533383414
1012241444153
115211a811a4
1224577750a1
13120119caa3
14841b0b9a1
154b9a6486d
hex2d9a59d39

12241444153 has 4 divisors (see below), whose sum is σ = 12299460688. Its totient is φ = 12183427620.

The previous prime is 12241444129. The next prime is 12241444183. The reversal of 12241444153 is 35144414221.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12241444153 - 217 = 12241313081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12241444183) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29007951 + ... + 29008372.

It is an arithmetic number, because the mean of its divisors is an integer number (3074865172).

Almost surely, 212241444153 is an apocalyptic number.

It is an amenable number.

12241444153 is a deficient number, since it is larger than the sum of its proper divisors (58016535).

12241444153 is an equidigital number, since it uses as much as digits as its factorization.

12241444153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 58016534.

The product of its digits is 15360, while the sum is 31.

Adding to 12241444153 its reverse (35144414221), we get a palindrome (47385858374).

The spelling of 12241444153 in words is "twelve billion, two hundred forty-one million, four hundred forty-four thousand, one hundred fifty-three".

Divisors: 1 211 58016323 12241444153