Base | Representation |
---|---|
bin | 11011110101011101011100… |
… | …001101111101001000000011 |
3 | 121001110022222222101210021020 |
4 | 123311131130031331020003 |
5 | 112021221202000000003 |
6 | 1112211233033000523 |
7 | 34533424334511105 |
oct | 3365353415751003 |
9 | 531408888353236 |
10 | 122421000000003 |
11 | 360094aaa9a1a1 |
12 | 11892015253143 |
13 | 5340334c14183 |
14 | 22332cab15575 |
15 | e246b7978d53 |
hex | 6f575c37d203 |
122421000000003 has 16 divisors (see below), whose sum is σ = 164745172294560. Its totient is φ = 80855592650496.
The previous prime is 122420999999993. The next prime is 122421000000029. The reversal of 122421000000003 is 300000000124221.
It is not a de Polignac number, because 122421000000003 - 233 = 122412410065411 is a prime.
It is a super-3 number, since 3×1224210000000033 (a number of 43 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (122421000002003) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 19606200 + ... + 25084757.
It is an arithmetic number, because the mean of its divisors is an integer number (10296573268410).
Almost surely, 2122421000000003 is an apocalyptic number.
122421000000003 is a deficient number, since it is larger than the sum of its proper divisors (42324172294557).
122421000000003 is a wasteful number, since it uses less digits than its factorization.
122421000000003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 44699446.
The product of its (nonzero) digits is 96, while the sum is 15.
Adding to 122421000000003 its reverse (300000000124221), we get a palindrome (422421000124224).
The spelling of 122421000000003 in words is "one hundred twenty-two trillion, four hundred twenty-one billion, three", and thus it is an aban number.
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