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12243311233 = 57803211811
BaseRepresentation
bin10110110011100001…
…00001101010000001
31011121020221122121121
423121300201222001
5200033241424413
65342520352241
7612254266636
oct133160415201
934536848547
1012243311233
115213036a3a
122458315681
1312016a487a
1484207618d
154b9cd2b8d
hex2d9c21a81

12243311233 has 4 divisors (see below), whose sum is σ = 12243580848. Its totient is φ = 12243041620.

The previous prime is 12243311177. The next prime is 12243311251. The reversal of 12243311233 is 33211334221.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12243311233 - 217 = 12243180161 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12243311198 and 12243311207.

It is not an unprimeable number, because it can be changed into a prime (12243312233) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 48103 + ... + 163708.

It is an arithmetic number, because the mean of its divisors is an integer number (3060895212).

Almost surely, 212243311233 is an apocalyptic number.

It is an amenable number.

12243311233 is a deficient number, since it is larger than the sum of its proper divisors (269615).

12243311233 is an equidigital number, since it uses as much as digits as its factorization.

12243311233 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 269614.

The product of its digits is 2592, while the sum is 25.

Adding to 12243311233 its reverse (33211334221), we get a palindrome (45454645454).

The spelling of 12243311233 in words is "twelve billion, two hundred forty-three million, three hundred eleven thousand, two hundred thirty-three".

Divisors: 1 57803 211811 12243311233