12244043313132 has 48 divisors (see below), whose sum is σ = 29554926075360. Its totient is φ = 3940566472192.

The previous prime is 12244043313121. The next prime is 12244043313163. The reversal of 12244043313132 is 23131334044221.

It is a junction number, because it is equal to n+sod(n) for n = 12244043313093 and 12244043313102.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 44279848 + ... + 44555504.

It is an arithmetic number, because the mean of its divisors is an integer number (615727626570).

Almost surely, 2^{12244043313132} is an apocalyptic number.

12244043313132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

12244043313132 is an abundant number, since it is smaller than the sum of its proper divisors (17310882762228).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12244043313132 is a wasteful number, since it uses less digits than its factorization.

12244043313132 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 403330 (or 403328 counting only the distinct ones).

The product of its (nonzero) digits is 41472, while the sum is 33.

Adding to 12244043313132 its reverse (23131334044221), we get a palindrome (35375377357353).

The spelling of 12244043313132 in words is "twelve trillion, two hundred forty-four billion, forty-three million, three hundred thirteen thousand, one hundred thirty-two".