Base | Representation |
---|---|
bin | 10110110011101000… |
… | …10101100000010011 |
3 | 1011121022211101201021 |
4 | 23121310111200103 |
5 | 200034020410120 |
6 | 5342554020311 |
7 | 612265626616 |
oct | 133164254023 |
9 | 34538741637 |
10 | 12244310035 |
11 | 52136593a1 |
12 | 2458717697 |
13 | 1201964389 |
14 | 84225617d |
15 | 4b9e2daaa |
hex | 2d9d15813 |
12244310035 has 4 divisors (see below), whose sum is σ = 14693172048. Its totient is φ = 9795448024.
The previous prime is 12244309991. The next prime is 12244310047. The reversal of 12244310035 is 53001344221.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12244310035 - 29 = 12244309523 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 12244309991 and 12244310009.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1224430999 + ... + 1224431008.
It is an arithmetic number, because the mean of its divisors is an integer number (3673293012).
Almost surely, 212244310035 is an apocalyptic number.
12244310035 is a deficient number, since it is larger than the sum of its proper divisors (2448862013).
12244310035 is an equidigital number, since it uses as much as digits as its factorization.
12244310035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2448862012.
The product of its (nonzero) digits is 2880, while the sum is 25.
Adding to 12244310035 its reverse (53001344221), we get a palindrome (65245654256).
The spelling of 12244310035 in words is "twelve billion, two hundred forty-four million, three hundred ten thousand, thirty-five".
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