Base | Representation |
---|---|
bin | 1011001001001011110100… |
… | …1110100001101100110001 |
3 | 1121101022122022112100111201 |
4 | 2302102331032201230301 |
5 | 3101220424341230230 |
6 | 42020403521211201 |
7 | 2403131265532105 |
oct | 262227516415461 |
9 | 47338568470451 |
10 | 12252421430065 |
11 | 39a424a528323 |
12 | 145a727190b01 |
13 | 6ab52432b71b |
14 | 30503dc2b905 |
15 | 163aa85e55ca |
hex | b24bd3a1b31 |
12252421430065 has 16 divisors (see below), whose sum is σ = 14780819347200. Its totient is φ = 9750021589440.
The previous prime is 12252421430027. The next prime is 12252421430071. The reversal of 12252421430065 is 56003412425221.
12252421430065 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 12252421430065 - 29 = 12252421429553 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1975447 + ... + 5329843.
It is an arithmetic number, because the mean of its divisors is an integer number (923801209200).
Almost surely, 212252421430065 is an apocalyptic number.
It is an amenable number.
12252421430065 is a deficient number, since it is larger than the sum of its proper divisors (2528397917135).
12252421430065 is a wasteful number, since it uses less digits than its factorization.
12252421430065 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3358272.
The product of its (nonzero) digits is 115200, while the sum is 37.
Adding to 12252421430065 its reverse (56003412425221), we get a palindrome (68255833855286).
The spelling of 12252421430065 in words is "twelve trillion, two hundred fifty-two billion, four hundred twenty-one million, four hundred thirty thousand, sixty-five".
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