12253400031331 has 4 divisors (see below), whose sum is σ = 12264045905664. Its totient is φ = 12242754157000.

The previous prime is 12253400031259. The next prime is 12253400031391. The reversal of 12253400031331 is 13313000435221.

12253400031331 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12253400031331 is a prime.

It is a super-2 number, since 2×12253400031331² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 12253400031331.

It is not an unprimeable number, because it can be changed into a prime (12253400031391) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5322935440 + ... + 5322937741.

It is an arithmetic number, because the mean of its divisors is an integer number (3066011476416).

Almost surely, 2^{12253400031331} is an apocalyptic number.

12253400031331 is a deficient number, since it is larger than the sum of its proper divisors (10645874333).

12253400031331 is a wasteful number, since it uses less digits than its factorization.

12253400031331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10645874332.

The product of its (nonzero) digits is 6480, while the sum is 28.

Adding to 12253400031331 its reverse (13313000435221), we get a palindrome (25566400466552).

The spelling of 12253400031331 in words is "twelve trillion, two hundred fifty-three billion, four hundred million, thirty-one thousand, three hundred thirty-one".