Base | Representation |
---|---|
bin | 10110110100101110… |
… | …01000110101000001 |
3 | 1011121221222220021112 |
4 | 23122113020311001 |
5 | 200043334330103 |
6 | 5343521333105 |
7 | 612436314623 |
oct | 133227106501 |
9 | 34557886245 |
10 | 12253433153 |
11 | 521881a765 |
12 | 245b797195 |
13 | 1203809a80 |
14 | 84354cc13 |
15 | 4bab31cd8 |
hex | 2da5c8d41 |
12253433153 has 16 divisors (see below), whose sum is σ = 13583077200. Its totient is φ = 10980458496.
The previous prime is 12253433119. The next prime is 12253433183. The reversal of 12253433153 is 35133435221.
It can be written as a sum of positive squares in 8 ways, for example, as 218684944 + 12034748209 = 14788^2 + 109703^2 .
It is a cyclic number.
It is not a de Polignac number, because 12253433153 - 212 = 12253429057 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12253433183) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 187601 + ... + 244337.
It is an arithmetic number, because the mean of its divisors is an integer number (848942325).
Almost surely, 212253433153 is an apocalyptic number.
12253433153 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
12253433153 is a deficient number, since it is larger than the sum of its proper divisors (1329644047).
12253433153 is a wasteful number, since it uses less digits than its factorization.
12253433153 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 57236.
The product of its digits is 32400, while the sum is 32.
Adding to 12253433153 its reverse (35133435221), we get a palindrome (47386868374).
The spelling of 12253433153 in words is "twelve billion, two hundred fifty-three million, four hundred thirty-three thousand, one hundred fifty-three".
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