122554505443 has 4 divisors (see below), whose sum is σ = 125162048160. Its totient is φ = 119946962728.

The previous prime is 122554505429. The next prime is 122554505453. The reversal of 122554505443 is 344505455221.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-122554505443 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 122554505396 and 122554505405.

It is not an unprimeable number, because it can be changed into a prime (122554505453) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1303771288 + ... + 1303771381.

It is an arithmetic number, because the mean of its divisors is an integer number (31290512040).

Almost surely, 2^122554505443 is an apocalyptic number.

122554505443 is a deficient number, since it is larger than the sum of its proper divisors (2607542717).

122554505443 is an equidigital number, since it uses as much as digits as its factorization.

122554505443 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2607542716.

The product of its (nonzero) digits is 480000, while the sum is 40.

The spelling of 122554505443 in words is "one hundred twenty-two billion, five hundred fifty-four million, five hundred five thousand, four hundred forty-three".