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122741534113 = 1111158321283
BaseRepresentation
bin111001001001111110…
…1110010110110100001
3102201211001211222021221
41302103331302312201
54002333313042423
6132215305015041
711603435553142
oct1622375626641
9381731758257
10122741534113
114806643a2a0
121b955a84481
13b7611839c3
145d254abac9
1532d59e1e5d
hex1c93f72da1

122741534113 has 4 divisors (see below), whose sum is σ = 133899855408. Its totient is φ = 111583212820.

The previous prime is 122741534107. The next prime is 122741534119. The reversal of 122741534113 is 311435147221.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 311435147221 = 1128312286111.

It is an interprime number because it is at equal distance from previous prime (122741534107) and next prime (122741534119).

It is a cyclic number.

It is not a de Polignac number, because 122741534113 - 25 = 122741534081 is a prime.

It is not an unprimeable number, because it can be changed into a prime (122741534119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5579160631 + ... + 5579160652.

It is an arithmetic number, because the mean of its divisors is an integer number (33474963852).

Almost surely, 2122741534113 is an apocalyptic number.

It is an amenable number.

122741534113 is a deficient number, since it is larger than the sum of its proper divisors (11158321295).

122741534113 is a wasteful number, since it uses less digits than its factorization.

122741534113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11158321294.

The product of its digits is 20160, while the sum is 34.

The spelling of 122741534113 in words is "one hundred twenty-two billion, seven hundred forty-one million, five hundred thirty-four thousand, one hundred thirteen".

Divisors: 1 11 11158321283 122741534113