1228310047 has 4 divisors (see below), whose sum is σ = 1228380160. Its totient is φ = 1228239936.

The previous prime is 1228309997. The next prime is 1228310063. The reversal of 1228310047 is 7400138221.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 1228310047 - 2¹¹ = 1228307999 is a prime.

It is a super-2 number, since 2×1228310047² = 3017491143122284418, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1228309997 and 1228310024.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1228310077) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16354 + ... + 52192.

It is an arithmetic number, because the mean of its divisors is an integer number (307095040).

Almost surely, 2^1228310047 is an apocalyptic number.

1228310047 is a deficient number, since it is larger than the sum of its proper divisors (70113).

1228310047 is an equidigital number, since it uses as much as digits as its factorization.

1228310047 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 70112.

The product of its (nonzero) digits is 2688, while the sum is 28.

The square root of 1228310047 is about 35047.2544859080. The cubic root of 1228310047 is about 1070.9503441399.

Adding to 1228310047 its reverse (7400138221), we get a palindrome (8628448268).

The spelling of 1228310047 in words is "one billion, two hundred twenty-eight million, three hundred ten thousand, forty-seven".