Base | Representation |
---|---|
bin | 10001111000000011000… |
… | …001000011101001000001 |
3 | 11100102202002111102102112 |
4 | 101320003001003221001 |
5 | 130111241240132421 |
6 | 2340154020225105 |
7 | 154515114250223 |
oct | 21700301035101 |
9 | 4312662442375 |
10 | 1228411255361 |
11 | 433a6a146824 |
12 | 17a0a853b195 |
13 | 8bab9788104 |
14 | 4365396c413 |
15 | 21e490da45b |
hex | 11e03043a41 |
1228411255361 has 4 divisors (see below), whose sum is σ = 1228925452500. Its totient is φ = 1227897058224.
The previous prime is 1228411255349. The next prime is 1228411255429. The reversal of 1228411255361 is 1635521148221.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 585898393600 + 642512861761 = 765440^2 + 801569^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1228411255361 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1228411255061) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 257094986 + ... + 257099763.
It is an arithmetic number, because the mean of its divisors is an integer number (307231363125).
Almost surely, 21228411255361 is an apocalyptic number.
It is an amenable number.
1228411255361 is a deficient number, since it is larger than the sum of its proper divisors (514197139).
1228411255361 is an equidigital number, since it uses as much as digits as its factorization.
1228411255361 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 514197138.
The product of its digits is 115200, while the sum is 41.
The spelling of 1228411255361 in words is "one trillion, two hundred twenty-eight billion, four hundred eleven million, two hundred fifty-five thousand, three hundred sixty-one".
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