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1228411255061 is a prime number
BaseRepresentation
bin10001111000000011000…
…001000011100100010101
311100102202002111102000102
4101320003001003210111
5130111241240130221
62340154020223445
7154515114246314
oct21700301034425
94312662442012
101228411255061
11433a6a146581
1217a0a853ab85
138bab9787c33
144365396c27b
1521e490da30b
hex11e03043915

1228411255061 has 2 divisors, whose sum is σ = 1228411255062. Its totient is φ = 1228411255060.

The previous prime is 1228411255021. The next prime is 1228411255063. The reversal of 1228411255061 is 1605521148221.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 998188820836 + 230222434225 = 999094^2 + 479815^2 .

It is an emirp because it is prime and its reverse (1605521148221) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1228411255061 is a prime.

It is a super-2 number, since 2×12284112550612 (a number of 25 digits) contains 22 as substring.

Together with 1228411255063, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1228411255063) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 614205627530 + 614205627531.

It is an arithmetic number, because the mean of its divisors is an integer number (614205627531).

Almost surely, 21228411255061 is an apocalyptic number.

It is an amenable number.

1228411255061 is a deficient number, since it is larger than the sum of its proper divisors (1).

1228411255061 is an equidigital number, since it uses as much as digits as its factorization.

1228411255061 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 38400, while the sum is 38.

The spelling of 1228411255061 in words is "one trillion, two hundred twenty-eight billion, four hundred eleven million, two hundred fifty-five thousand, sixty-one".