Base | Representation |
---|---|
bin | 11011111101111000111101… |
… | …100001000100111100010111 |
3 | 121010111201021202220112010101 |
4 | 123331320331201010330113 |
5 | 112110214111202112043 |
6 | 1113333321004234531 |
7 | 34623323143163443 |
oct | 3375707541047427 |
9 | 533451252815111 |
10 | 123000305504023 |
11 | 36212155933652 |
12 | 1196634953ba47 |
13 | 5382b5733398c |
14 | 225336476d823 |
15 | e347c0ae424d |
hex | 6fde3d844f17 |
123000305504023 has 4 divisors (see below), whose sum is σ = 123000359615568. Its totient is φ = 123000251392480.
The previous prime is 123000305503853. The next prime is 123000305504099. The reversal of 123000305504023 is 320405503000321.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 123000305504023 - 213 = 123000305495831 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 123000305503982 and 123000305504000.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (123000305504723) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23489443 + ... + 28244548.
It is an arithmetic number, because the mean of its divisors is an integer number (30750089903892).
Almost surely, 2123000305504023 is an apocalyptic number.
123000305504023 is a deficient number, since it is larger than the sum of its proper divisors (54111545).
123000305504023 is an equidigital number, since it uses as much as digits as its factorization.
123000305504023 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 54111544.
The product of its (nonzero) digits is 10800, while the sum is 28.
Adding to 123000305504023 its reverse (320405503000321), we get a palindrome (443405808504344).
The spelling of 123000305504023 in words is "one hundred twenty-three trillion, three hundred five million, five hundred four thousand, twenty-three".
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