Base | Representation |
---|---|
bin | 10110111010010001… |
… | …11001111000001111 |
3 | 1011202012200110000012 |
4 | 23131020321320033 |
5 | 200142302033201 |
6 | 5352304223435 |
7 | 613543363061 |
oct | 133510717017 |
9 | 34665613005 |
10 | 12300033551 |
11 | 5242059293 |
12 | 247330ab7b |
13 | 1210374980 |
14 | 8497dd731 |
15 | 4bec895bb |
hex | 2dd239e0f |
12300033551 has 4 divisors (see below), whose sum is σ = 13246189992. Its totient is φ = 11353877112.
The previous prime is 12300033521. The next prime is 12300033563. The reversal of 12300033551 is 15533000321.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12300033551 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12300033521) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 473078201 + ... + 473078226.
It is an arithmetic number, because the mean of its divisors is an integer number (3311547498).
Almost surely, 212300033551 is an apocalyptic number.
12300033551 is a deficient number, since it is larger than the sum of its proper divisors (946156441).
12300033551 is an equidigital number, since it uses as much as digits as its factorization.
12300033551 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 946156440.
The product of its (nonzero) digits is 1350, while the sum is 23.
Adding to 12300033551 its reverse (15533000321), we get a palindrome (27833033872).
The spelling of 12300033551 in words is "twelve billion, three hundred million, thirty-three thousand, five hundred fifty-one".
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