Search a number
-
+
1230004555 = 51318923147
BaseRepresentation
bin100100101010000…
…0110000101001011
310011201110201001021
41021110012011023
510004340121210
6322015133311
742323603053
oct11124060513
93151421037
101230004555
1158133a69a
122a3b14237
13167a9b560
14b9500563
1572eb5bda
hex4950614b

1230004555 has 8 divisors (see below), whose sum is σ = 1589544432. Its totient is φ = 908311008.

The previous prime is 1230004547. The next prime is 1230004597. The reversal of 1230004555 is 5554000321.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1230004555 - 23 = 1230004547 is a prime.

It is a super-4 number, since 4×12300045554 (a number of 37 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 9461509 + ... + 9461638.

It is an arithmetic number, because the mean of its divisors is an integer number (198693054).

Almost surely, 21230004555 is an apocalyptic number.

1230004555 is a deficient number, since it is larger than the sum of its proper divisors (359539877).

1230004555 is a wasteful number, since it uses less digits than its factorization.

1230004555 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 18923165.

The product of its (nonzero) digits is 3000, while the sum is 25.

The square root of 1230004555 is about 35071.4207724751. The cubic root of 1230004555 is about 1071.4425922948.

Adding to 1230004555 its reverse (5554000321), we get a palindrome (6784004876).

The spelling of 1230004555 in words is "one billion, two hundred thirty million, four thousand, five hundred fifty-five".

Divisors: 1 5 13 65 18923147 94615735 246000911 1230004555