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12300102200103 = 34100034066701
BaseRepresentation
bin1011001011111101011100…
…1110001110101100100111
31121112212201021022102201120
42302333113032032230213
53103011102130400403
642054331113425023
72406436666432344
oct262772716165447
947485637272646
1012300102200103
113a124980355a3
121467a1340b173
136b2b82752513
143074845257cb
15164e4956ae53
hexb2fd738eb27

12300102200103 has 4 divisors (see below), whose sum is σ = 16400136266808. Its totient is φ = 8200068133400.

The previous prime is 12300102200051. The next prime is 12300102200147. The reversal of 12300102200103 is 30100220100321.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12300102200103 - 212 = 12300102196007 is a prime.

It is a super-2 number, since 2×123001022001032 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12300102200303) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2050017033348 + ... + 2050017033353.

It is an arithmetic number, because the mean of its divisors is an integer number (4100034066702).

Almost surely, 212300102200103 is an apocalyptic number.

12300102200103 is a deficient number, since it is larger than the sum of its proper divisors (4100034066705).

12300102200103 is an equidigital number, since it uses as much as digits as its factorization.

12300102200103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4100034066704.

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 12300102200103 its reverse (30100220100321), we get a palindrome (42400322300424).

The spelling of 12300102200103 in words is "twelve trillion, three hundred billion, one hundred two million, two hundred thousand, one hundred three".

Divisors: 1 3 4100034066701 12300102200103