Base | Representation |
---|---|
bin | 1011001011111101011100… |
… | …1110001110101100100111 |
3 | 1121112212201021022102201120 |
4 | 2302333113032032230213 |
5 | 3103011102130400403 |
6 | 42054331113425023 |
7 | 2406436666432344 |
oct | 262772716165447 |
9 | 47485637272646 |
10 | 12300102200103 |
11 | 3a124980355a3 |
12 | 1467a1340b173 |
13 | 6b2b82752513 |
14 | 3074845257cb |
15 | 164e4956ae53 |
hex | b2fd738eb27 |
12300102200103 has 4 divisors (see below), whose sum is σ = 16400136266808. Its totient is φ = 8200068133400.
The previous prime is 12300102200051. The next prime is 12300102200147. The reversal of 12300102200103 is 30100220100321.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12300102200103 - 212 = 12300102196007 is a prime.
It is a super-2 number, since 2×123001022001032 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12300102200303) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2050017033348 + ... + 2050017033353.
It is an arithmetic number, because the mean of its divisors is an integer number (4100034066702).
Almost surely, 212300102200103 is an apocalyptic number.
12300102200103 is a deficient number, since it is larger than the sum of its proper divisors (4100034066705).
12300102200103 is an equidigital number, since it uses as much as digits as its factorization.
12300102200103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4100034066704.
The product of its (nonzero) digits is 72, while the sum is 15.
Adding to 12300102200103 its reverse (30100220100321), we get a palindrome (42400322300424).
The spelling of 12300102200103 in words is "twelve trillion, three hundred billion, one hundred two million, two hundred thousand, one hundred three".
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