Base | Representation |
---|---|
bin | 10001111001100100000… |
… | …001100101100001000101 |
3 | 11100120221111222110002120 |
4 | 101321210001211201011 |
5 | 130123104412042234 |
6 | 2341023320000153 |
7 | 154603336103664 |
oct | 21714401454105 |
9 | 4316844873076 |
10 | 1230038784069 |
11 | 434724910177 |
12 | 17a481600059 |
13 | 8bcb8a0c054 |
14 | 43769b8addb |
15 | 21ee1e26049 |
hex | 11e64065845 |
1230038784069 has 4 divisors (see below), whose sum is σ = 1640051712096. Its totient is φ = 820025856044.
The previous prime is 1230038784019. The next prime is 1230038784137. The reversal of 1230038784069 is 9604878300321.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1230038784069 - 213 = 1230038775877 is a prime.
It is a super-2 number, since 2×12300387840692 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1230038784019) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 205006464009 + ... + 205006464014.
It is an arithmetic number, because the mean of its divisors is an integer number (410012928024).
Almost surely, 21230038784069 is an apocalyptic number.
It is an amenable number.
1230038784069 is a deficient number, since it is larger than the sum of its proper divisors (410012928027).
1230038784069 is an equidigital number, since it uses as much as digits as its factorization.
1230038784069 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 410012928026.
The product of its (nonzero) digits is 1741824, while the sum is 51.
The spelling of 1230038784069 in words is "one trillion, two hundred thirty billion, thirty-eight million, seven hundred eighty-four thousand, sixty-nine".
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