Base | Representation |
---|---|
bin | 1011001011111111000011… |
… | …1001101001110000000001 |
3 | 1121112220211021222000121111 |
4 | 2302333300321221300001 |
5 | 3103012442422413010 |
6 | 42054441543323321 |
7 | 2406453450331162 |
oct | 262776071516001 |
9 | 47486737860544 |
10 | 12300533013505 |
11 | 3a12699237030 |
12 | 1467b13750541 |
13 | 6b2c20a920a9 |
14 | 3074c582b769 |
15 | 164e722b958a |
hex | b2ff0e69c01 |
12300533013505 has 16 divisors (see below), whose sum is σ = 16950016785600. Its totient is φ = 8475008391360.
The previous prime is 12300533013469. The next prime is 12300533013533. The reversal of 12300533013505 is 50531033500321.
12300533013505 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 12300533013505 - 211 = 12300533011457 is a prime.
It is a super-3 number, since 3×123005330135053 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5885421450 + ... + 5885423539.
It is an arithmetic number, because the mean of its divisors is an integer number (1059376049100).
Almost surely, 212300533013505 is an apocalyptic number.
It is an amenable number.
12300533013505 is a deficient number, since it is larger than the sum of its proper divisors (4649483772095).
12300533013505 is a wasteful number, since it uses less digits than its factorization.
12300533013505 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11770845024.
The product of its (nonzero) digits is 20250, while the sum is 31.
Adding to 12300533013505 its reverse (50531033500321), we get a palindrome (62831566513826).
The spelling of 12300533013505 in words is "twelve trillion, three hundred billion, five hundred thirty-three million, thirteen thousand, five hundred five".
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