Base | Representation |
---|---|
bin | 11011111110000010010001… |
… | …010010111100011101101101 |
3 | 121010112200002101020100100022 |
4 | 123332002101102330131231 |
5 | 112110400044030120023 |
6 | 1113342052511011525 |
7 | 34624125634521461 |
oct | 3376022122743555 |
9 | 533480071210308 |
10 | 123010301020013 |
11 | 36216415065770 |
12 | 11968278b09ba5 |
13 | 5383a8b111194 |
14 | 2253a320864a1 |
15 | e34ba83b87c8 |
hex | 6fe0914bc76d |
123010301020013 has 4 divisors (see below), whose sum is σ = 134193055658208. Its totient is φ = 111827546381820.
The previous prime is 123010301019979. The next prime is 123010301020069. The reversal of 123010301020013 is 310020103010321.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 123010301020013 - 232 = 123006006052717 is a prime.
It is a super-2 number, since 2×1230103010200132 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 123010301019973 and 123010301020000.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (123010301020513) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5591377319081 + ... + 5591377319102.
It is an arithmetic number, because the mean of its divisors is an integer number (33548263914552).
Almost surely, 2123010301020013 is an apocalyptic number.
It is an amenable number.
123010301020013 is a deficient number, since it is larger than the sum of its proper divisors (11182754638195).
123010301020013 is a wasteful number, since it uses less digits than its factorization.
123010301020013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11182754638194.
The product of its (nonzero) digits is 108, while the sum is 17.
Adding to 123010301020013 its reverse (310020103010321), we get a palindrome (433030404030334).
The spelling of 123010301020013 in words is "one hundred twenty-three trillion, ten billion, three hundred one million, twenty thousand, thirteen".
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