Base | Representation |
---|---|
bin | 1011001100000001010001… |
… | …1111000101111110011010 |
3 | 1121112222100220100122122122 |
4 | 2303000110133011332122 |
5 | 3103020203241443002 |
6 | 42055021111421242 |
7 | 2406504320026031 |
oct | 263002437057632 |
9 | 47488326318578 |
10 | 12301130031002 |
11 | 3a1297523811a |
12 | 146805b684822 |
13 | 6b2cb7685297 |
14 | 307540c39718 |
15 | 164ea98e86a2 |
hex | b30147c5f9a |
12301130031002 has 4 divisors (see below), whose sum is σ = 18451695046506. Its totient is φ = 6150565015500.
The previous prime is 12301130030999. The next prime is 12301130031037. The reversal of 12301130031002 is 20013003110321.
12301130031002 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 11314403688721 + 986726342281 = 3363689^2 + 993341^2 .
It is a super-2 number, since 2×123011300310022 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3075282507749 + ... + 3075282507752.
Almost surely, 212301130031002 is an apocalyptic number.
12301130031002 is a deficient number, since it is larger than the sum of its proper divisors (6150565015504).
12301130031002 is an equidigital number, since it uses as much as digits as its factorization.
12301130031002 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6150565015503.
The product of its (nonzero) digits is 108, while the sum is 17.
Adding to 12301130031002 its reverse (20013003110321), we get a palindrome (32314133141323).
The spelling of 12301130031002 in words is "twelve trillion, three hundred one billion, one hundred thirty million, thirty-one thousand, two".
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