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12302013223 = 41300049103
BaseRepresentation
bin10110111010100000…
…11101001100100111
31011202100102000121101
423131100131030213
5200143303410343
65352414500531
7613566246523
oct133520351447
934670360541
1012302013223
115243190685
122473b04747
1312108b8a86
14849b96d83
154c002ae4d
hex2dd41d327

12302013223 has 4 divisors (see below), whose sum is σ = 12602062368. Its totient is φ = 12001964080.

The previous prime is 12302013187. The next prime is 12302013253. The reversal of 12302013223 is 32231020321.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12302013223 - 29 = 12302012711 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 12302013223.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12302013253) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 150024511 + ... + 150024592.

It is an arithmetic number, because the mean of its divisors is an integer number (3150515592).

Almost surely, 212302013223 is an apocalyptic number.

12302013223 is a deficient number, since it is larger than the sum of its proper divisors (300049145).

12302013223 is an equidigital number, since it uses as much as digits as its factorization.

12302013223 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 300049144.

The product of its (nonzero) digits is 432, while the sum is 19.

Adding to 12302013223 its reverse (32231020321), we get a palindrome (44533033544).

The spelling of 12302013223 in words is "twelve billion, three hundred two million, thirteen thousand, two hundred twenty-three".

Divisors: 1 41 300049103 12302013223