Base | Representation |
---|---|
bin | 10001111001101110001… |
… | …110110011001100010001 |
3 | 11100121101110012010210021 |
4 | 101321232032303030101 |
5 | 130123432231120423 |
6 | 2341052314103441 |
7 | 154610515431304 |
oct | 21715616631421 |
9 | 4317343163707 |
10 | 1230210020113 |
11 | 434802537368 |
12 | 17a50aa1ab81 |
13 | 8c015334b59 |
14 | 43784802b3b |
15 | 22001e9c95d |
hex | 11e6e3b3311 |
1230210020113 has 4 divisors (see below), whose sum is σ = 1256384701440. Its totient is φ = 1204035338788.
The previous prime is 1230210020111. The next prime is 1230210020141. The reversal of 1230210020113 is 3110200120321.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1230210020113 - 21 = 1230210020111 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1230210020111) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13087340593 + ... + 13087340686.
It is an arithmetic number, because the mean of its divisors is an integer number (314096175360).
Almost surely, 21230210020113 is an apocalyptic number.
It is an amenable number.
1230210020113 is a deficient number, since it is larger than the sum of its proper divisors (26174681327).
1230210020113 is an equidigital number, since it uses as much as digits as its factorization.
1230210020113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 26174681326.
The product of its (nonzero) digits is 72, while the sum is 16.
Adding to 1230210020113 its reverse (3110200120321), we get a palindrome (4340410140434).
The spelling of 1230210020113 in words is "one trillion, two hundred thirty billion, two hundred ten million, twenty thousand, one hundred thirteen".
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