Base | Representation |
---|---|
bin | 10001111001101110001… |
… | …111111100111011010101 |
3 | 11100121101110202111002012 |
4 | 101321232033330323111 |
5 | 130123432320302013 |
6 | 2341052324354005 |
7 | 154610521126652 |
oct | 21715617747325 |
9 | 4317343674065 |
10 | 1230210322133 |
11 | 434802723271 |
12 | 17a50ab45905 |
13 | 8c01540c470 |
14 | 43784880c29 |
15 | 2200200c1a8 |
hex | 11e6e3fced5 |
1230210322133 has 4 divisors (see below), whose sum is σ = 1324841885388. Its totient is φ = 1135578758880.
The previous prime is 1230210322079. The next prime is 1230210322141. The reversal of 1230210322133 is 3312230120321.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 848209686289 + 382000635844 = 920983^2 + 618062^2 .
It is a cyclic number.
It is not a de Polignac number, because 1230210322133 - 224 = 1230193544917 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 1230210322099 and 1230210322108.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1230210322183) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 47315781608 + ... + 47315781633.
It is an arithmetic number, because the mean of its divisors is an integer number (331210471347).
Almost surely, 21230210322133 is an apocalyptic number.
1230210322133 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
1230210322133 is a deficient number, since it is larger than the sum of its proper divisors (94631563255).
1230210322133 is an equidigital number, since it uses as much as digits as its factorization.
1230210322133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 94631563254.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 1230210322133 its reverse (3312230120321), we get a palindrome (4542440442454).
The spelling of 1230210322133 in words is "one trillion, two hundred thirty billion, two hundred ten million, three hundred twenty-two thousand, one hundred thirty-three".
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