Base | Representation |
---|---|
bin | 1011001100000101101110… |
… | …0110110010101001100101 |
3 | 1121120002110001120111210111 |
4 | 2303001123212302221211 |
5 | 3103030124221400313 |
6 | 42055335334053021 |
7 | 2406546016044142 |
oct | 263013346625145 |
9 | 47502401514714 |
10 | 12302323231333 |
11 | 3a1342781a1a3 |
12 | 14683331aa171 |
13 | 6b3147938795 |
14 | 3076154b93c9 |
15 | 16502953e43d |
hex | b305b9b2a65 |
12302323231333 has 4 divisors (see below), whose sum is σ = 12302330257728. Its totient is φ = 12302316204940.
The previous prime is 12302323231313. The next prime is 12302323231337. The reversal of 12302323231333 is 33313232320321.
12302323231333 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is not a de Polignac number, because 12302323231333 - 25 = 12302323231301 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 12302323231295 and 12302323231304.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12302323231337) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1455738 + ... + 5169508.
It is an arithmetic number, because the mean of its divisors is an integer number (3075582564432).
Almost surely, 212302323231333 is an apocalyptic number.
It is an amenable number.
12302323231333 is a deficient number, since it is larger than the sum of its proper divisors (7026395).
12302323231333 is an equidigital number, since it uses as much as digits as its factorization.
12302323231333 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7026394.
The product of its (nonzero) digits is 34992, while the sum is 31.
Adding to 12302323231333 its reverse (33313232320321), we get a palindrome (45615555551654).
The spelling of 12302323231333 in words is "twelve trillion, three hundred two billion, three hundred twenty-three million, two hundred thirty-one thousand, three hundred thirty-three".
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