123031254010033 has 4 divisors (see below), whose sum is σ = 123223190444388. Its totient is φ = 122839317575680.

The previous prime is 123031254009977. The next prime is 123031254010039. The reversal of 123031254010033 is 330010452130321.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 76984620231744 + 46046633778289 = 8774088^2 + 6785767^2 .

It is a cyclic number.

It is not a de Polignac number, because 123031254010033 - 2²⁵ = 123031220455601 is a prime.

It is a super-3 number, since 3×123031254010033³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 123031254009983 and 123031254010010.

It is not an unprimeable number, because it can be changed into a prime (123031254010039) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 95968216216 + ... + 95968217497.

It is an arithmetic number, because the mean of its divisors is an integer number (30805797611097).

Almost surely, 2^{123031254010033} is an apocalyptic number.

It is an amenable number.

123031254010033 is a deficient number, since it is larger than the sum of its proper divisors (191936434355).

123031254010033 is an equidigital number, since it uses as much as digits as its factorization.

123031254010033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 191936434354.

The product of its (nonzero) digits is 6480, while the sum is 28.

The spelling of 123031254010033 in words is "one hundred twenty-three trillion, thirty-one billion, two hundred fifty-four million, ten thousand, thirty-three".