Base | Representation |
---|---|
bin | 10001111001110100111… |
… | …101111011111110000011 |
3 | 11100121200022212011002212 |
4 | 101321310331323332003 |
5 | 130124200144241011 |
6 | 2341111432332335 |
7 | 154613360201603 |
oct | 21716475737603 |
9 | 4317608764085 |
10 | 1230323040131 |
11 | 434860310a39 |
12 | 17a5408440ab |
13 | 8c0328869c3 |
14 | 43795822c03 |
15 | 2200bd7508b |
hex | 11e74f7bf83 |
1230323040131 has 6 divisors (see below), whose sum is σ = 1234913806932. Its totient is φ = 1225749276440.
The previous prime is 1230323040103. The next prime is 1230323040227. The reversal of 1230323040131 is 1310403230321.
It is not a de Polignac number, because 1230323040131 - 218 = 1230322777987 is a prime.
It is a super-2 number, since 2×12303230401312 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1230323040097 and 1230323040106.
It is not an unprimeable number, because it can be changed into a prime (1230323040631) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 8428925 + ... + 8573646.
It is an arithmetic number, because the mean of its divisors is an integer number (205818967822).
Almost surely, 21230323040131 is an apocalyptic number.
1230323040131 is a deficient number, since it is larger than the sum of its proper divisors (4590766801).
1230323040131 is an frugal number, since it uses more digits than its factorization.
1230323040131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 17003109 (or 17002840 counting only the distinct ones).
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 1230323040131 its reverse (1310403230321), we get a palindrome (2540726270452).
The spelling of 1230323040131 in words is "one trillion, two hundred thirty billion, three hundred twenty-three million, forty thousand, one hundred thirty-one".
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