Base | Representation |
---|---|
bin | 1011001100001001100100… |
… | …0000000000110111000011 |
3 | 1121120012002211202001022210 |
4 | 2303002121000000313003 |
5 | 3103034231413101230 |
6 | 42100025451033203 |
7 | 2406613364064525 |
oct | 263023100006703 |
9 | 47505084661283 |
10 | 12303353253315 |
11 | 3a13906188a33 |
12 | 146858013b803 |
13 | 6b3280157947 |
14 | 3076b21dda15 |
15 | 165089ba0eb0 |
hex | b3099000dc3 |
12303353253315 has 8 divisors (see below), whose sum is σ = 19685365205328. Its totient is φ = 6561788401760.
The previous prime is 12303353253241. The next prime is 12303353253391. The reversal of 12303353253315 is 51335235330321.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 12303353253315 - 212 = 12303353249219 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 410111775096 + ... + 410111775125.
It is an arithmetic number, because the mean of its divisors is an integer number (2460670650666).
Almost surely, 212303353253315 is an apocalyptic number.
12303353253315 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
12303353253315 is a deficient number, since it is larger than the sum of its proper divisors (7382011952013).
12303353253315 is an equidigital number, since it uses as much as digits as its factorization.
12303353253315 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 820223550229.
The product of its (nonzero) digits is 364500, while the sum is 39.
Adding to 12303353253315 its reverse (51335235330321), we get a palindrome (63638588583636).
The spelling of 12303353253315 in words is "twelve trillion, three hundred three billion, three hundred fifty-three million, two hundred fifty-three thousand, three hundred fifteen".
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