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12304214303 = 71394343951
BaseRepresentation
bin10110111010110001…
…10110100100011111
31011202111112211220212
423131120312210133
5200144334324203
65352534003035
7613624044623
oct133530664437
934674484825
1012304214303
115244454357
1224747a647b
1312111a98a4
1484a1ab183
154c03131d8
hex2dd63691f

12304214303 has 8 divisors (see below), whose sum is σ = 12480961536. Its totient is φ = 12127563000.

The previous prime is 12304214257. The next prime is 12304214333. The reversal of 12304214303 is 30341240321.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 12304214303 - 26 = 12304214239 is a prime.

It is a super-2 number, since 2×123042143032 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12304214333) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 257978 + ... + 301928.

It is an arithmetic number, because the mean of its divisors is an integer number (1560120192).

Almost surely, 212304214303 is an apocalyptic number.

12304214303 is a deficient number, since it is larger than the sum of its proper divisors (176747233).

12304214303 is an equidigital number, since it uses as much as digits as its factorization.

12304214303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 47965.

The product of its (nonzero) digits is 1728, while the sum is 23.

Adding to 12304214303 its reverse (30341240321), we get a palindrome (42645454624).

The spelling of 12304214303 in words is "twelve billion, three hundred four million, two hundred fourteen thousand, three hundred three".

Divisors: 1 71 3943 43951 279953 3120521 173298793 12304214303