Base | Representation |
---|---|
bin | 10001111001111011000… |
… | …000010101010000111011 |
3 | 11100121221101110021111111 |
4 | 101321323000111100323 |
5 | 130124402112100243 |
6 | 2341125451341151 |
7 | 154616030152315 |
oct | 21717300252073 |
9 | 4317841407444 |
10 | 1230424331323 |
11 | 434902504570 |
12 | 17a56a7517b7 |
13 | 8c04a860115 |
14 | 437a506c7b5 |
15 | 22015bd239d |
hex | 11e7b01543b |
1230424331323 has 4 divisors (see below), whose sum is σ = 1342281088728. Its totient is φ = 1118567573920.
The previous prime is 1230424331321. The next prime is 1230424331333. The reversal of 1230424331323 is 3231334240321.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1230424331323 - 21 = 1230424331321 is a prime.
It is a super-2 number, since 2×12304243313232 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1230424331321) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 55928378686 + ... + 55928378707.
It is an arithmetic number, because the mean of its divisors is an integer number (335570272182).
Almost surely, 21230424331323 is an apocalyptic number.
1230424331323 is a deficient number, since it is larger than the sum of its proper divisors (111856757405).
1230424331323 is a wasteful number, since it uses less digits than its factorization.
1230424331323 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 111856757404.
The product of its (nonzero) digits is 31104, while the sum is 31.
Adding to 1230424331323 its reverse (3231334240321), we get a palindrome (4461758571644).
The spelling of 1230424331323 in words is "one trillion, two hundred thirty billion, four hundred twenty-four million, three hundred thirty-one thousand, three hundred twenty-three".
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