Base | Representation |
---|---|
bin | 11011111110101000010001… |
… | …001000010011100110111111 |
3 | 121010200120101202111122012211 |
4 | 123332220101020103212333 |
5 | 112112032123201424133 |
6 | 1113412521203441251 |
7 | 34630101656641201 |
oct | 3376502110234677 |
9 | 533616352448184 |
10 | 123051100420543 |
11 | 362317512851a9 |
12 | 11974164686227 |
13 | 53878909967b9 |
14 | 22559c28a4771 |
15 | e35c95159bcd |
hex | 6fea112139bf |
123051100420543 has 4 divisors (see below), whose sum is σ = 123067310558608. Its totient is φ = 123034890282480.
The previous prime is 123051100420537. The next prime is 123051100420609. The reversal of 123051100420543 is 345024001150321.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 123051100420543 - 25 = 123051100420511 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (123051100420343) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8105057646 + ... + 8105072827.
It is an arithmetic number, because the mean of its divisors is an integer number (30766827639652).
Almost surely, 2123051100420543 is an apocalyptic number.
123051100420543 is a deficient number, since it is larger than the sum of its proper divisors (16210138065).
123051100420543 is an equidigital number, since it uses as much as digits as its factorization.
123051100420543 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16210138064.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 123051100420543 its reverse (345024001150321), we get a palindrome (468075101570864).
The spelling of 123051100420543 in words is "one hundred twenty-three trillion, fifty-one billion, one hundred million, four hundred twenty thousand, five hundred forty-three".
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