1230540433 has 4 divisors (see below), whose sum is σ = 1244366820. Its totient is φ = 1216714048.

The previous prime is 1230540371. The next prime is 1230540497. The reversal of 1230540433 is 3340450321.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 218537089 + 1012003344 = 14783^2 + 31812^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1230540433 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1230540398 and 1230540407.

It is not an unprimeable number, because it can be changed into a prime (1230540533) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6913060 + ... + 6913237.

It is an arithmetic number, because the mean of its divisors is an integer number (311091705).

Almost surely, 2^1230540433 is an apocalyptic number.

It is an amenable number.

1230540433 is a deficient number, since it is larger than the sum of its proper divisors (13826387).

1230540433 is an equidigital number, since it uses as much as digits as its factorization.

1230540433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13826386.

The product of its (nonzero) digits is 4320, while the sum is 25.

The square root of 1230540433 is about 35079.0597507972. The cubic root of 1230540433 is about 1071.5981687245.

Adding to 1230540433 its reverse (3340450321), we get a palindrome (4570990754).

The spelling of 1230540433 in words is "one billion, two hundred thirty million, five hundred forty thousand, four hundred thirty-three".