Base | Representation |
---|---|
bin | 1011001100010001100100… |
… | …1010100011101111000101 |
3 | 1121120101122200210221222022 |
4 | 2303010121022203233011 |
5 | 3103103132344020003 |
6 | 42101023102212525 |
7 | 2410020563641124 |
oct | 263043112435705 |
9 | 47511580727868 |
10 | 12305503501253 |
11 | 3a14809a17046 |
12 | 1468a80284145 |
13 | 6b35337899c1 |
14 | 307837a09abb |
15 | 165163841738 |
hex | b31192a3bc5 |
12305503501253 has 4 divisors (see below), whose sum is σ = 12305580672960. Its totient is φ = 12305426329548.
The previous prime is 12305503501243. The next prime is 12305503501387. The reversal of 12305503501253 is 35210530550321.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 12305503501253 - 210 = 12305503500229 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12305503501243) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 38346173 + ... + 38665746.
It is an arithmetic number, because the mean of its divisors is an integer number (3076395168240).
Almost surely, 212305503501253 is an apocalyptic number.
It is an amenable number.
12305503501253 is a deficient number, since it is larger than the sum of its proper divisors (77171707).
12305503501253 is an equidigital number, since it uses as much as digits as its factorization.
12305503501253 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 77171706.
The product of its (nonzero) digits is 67500, while the sum is 35.
The spelling of 12305503501253 in words is "twelve trillion, three hundred five billion, five hundred three million, five hundred one thousand, two hundred fifty-three".
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