12310013431 has 4 divisors (see below), whose sum is σ = 12381169752. Its totient is φ = 12238857112.

The previous prime is 12310013411. The next prime is 12310013449. The reversal of 12310013431 is 13431001321.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13431001321 = 17449 ⋅769729.

It is a cyclic number.

It is not a de Polignac number, because 12310013431 - 2⁵ = 12310013399 is a prime.

It is a super-2 number, since 2×12310013431² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12310013399 and 12310013408.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12310013411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35577901 + ... + 35578246.

It is an arithmetic number, because the mean of its divisors is an integer number (3095292438).

Almost surely, 2^12310013431 is an apocalyptic number.

12310013431 is a deficient number, since it is larger than the sum of its proper divisors (71156321).

12310013431 is an equidigital number, since it uses as much as digits as its factorization.

12310013431 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 71156320.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 12310013431 its reverse (13431001321), we get a palindrome (25741014752).

The spelling of 12310013431 in words is "twelve billion, three hundred ten million, thirteen thousand, four hundred thirty-one".